Problem 4: Traffic Assignment (25 marks) Main Street East and Main Street West are one-way roads within the CBD of Hawki
Posted: Fri May 27, 2022 7:15 am
Problem 4: Traffic Assignment (25 marks) Main Street East and Main Street West are one-way roads within the CBD of Hawkins as shown in Figure 3. Eastbound traffic along Main Street can only use Main Street East to reach Hawkins Station and other land uses to the east of the CBD. Due to the development of Palace Arcade Hills, there will be further traffic demands placed on Main Street, and Mayor Kline is concerned about the traffic on Main Street, particularly in the Eastbound direction. A possible solution is to convert both Main Street East and Main Street West into two-way roads to increase road capacity. Hawkins M Station Main Street East Main Street Main Street West 2 3 D Main Street East Main Street Street 4 Main Street West Figure 3: Map of route for Eastbound Traffic along Main Street. Table 11 presents the properties of each link in the existing network relevant to Eastbound travel along Main Street. Table 11: Link properties of existing infrastructure (x, represents the link volume on link "A") Link Link Cost (travel Link Road Name Direction of Travel Link Volume Capacity (veh/hr) (veh/hr) Travel time) Function Time (minutes) 1 Main Street Eastbound 1800 X₂ (1800) +3 2 Main Street East Eastbound 1200 +8 1200/ 3 Main Street Eastbound 1800 * = (1800) + 3 4 Main Street West Westbound 1200 t₂ = %4 1200- +8 The proposed change will allow Eastbound traffic to travel along Main Street West and also utilise Hawkins Highway northbound. However, the right turn from Main Street East into Hawkins Highway in the southbound direction will be banned due to safety concerns and excessive congestion southbound along Hawkins Highway. A 1 20 Main B с
Assess the traffic conditions and potential future traffic assignment for vehicles travelling Eastbound along Main Street. a) If the existing peak demand for Eastbound traffic along Main Street is 1200 vehicles/hour (for vehicles travelling from Node A to Node D), what are the current link and route travel times for journeys from Node A to Node D? What is the volume to capacity ratio for each link of this journey? Is this currently a problem for Hawkins? Provide a clear statement and reasoning. (5 marks) b) The forecasted Eastbound traffic demand along Main street is 1800 vehicles/hour (for vehicles travelling from Node A to Node D) once the proposed developments are completed, what will the future link and route travel times be for journeys from Node A to Node D? What is the volume to capacity ratio of each link of this journey? Will it be a problem for Hawkins in the future? Provide a clear statement and reasoning. (5 marks) c) In order to assess the proposal put forward by Mayor Kline where both Main Street East and Main Street West become two-way roads, it is necessary to collect further information about the network as in this context there will be more routes for users to choose. Table 12 presents the additional data required to make an assessment about the Eastbound traffic conditions. Node A is identical to Node A in Figure 3, however Node D is now labelled as Node F due to the change in infrastructure. Draw the node and link network diagram given the information in Table 12 and identify all possible routes that could be used by motorists travelling Eastbound along Main Street. Note that looped routes (routes containing the same link twice) should not be considered. (5 marks) Table 12: Link properties of proposed infrastructure (x, represents the link volume on link "A") Link Link Link Node Road Name Direction Capacity of Travel (veh/hr) Travel Link Cost (travel time) Function (minutes) Label Volume (veh/hr) Time Label %₂ 1 A to B Main Street Eastbound 1800 %₂ f₂ 1800 2 B to C Main Street East Eastbound 800 1₂ B to D Main Street West Eastbound 600 1₂ C to E Main Street East Eastbound 800 X4 74 D to E Main Street West Eastbound 600 ts E to F Main Street Eastbound 1800 to D to C Hawkins Highway Northbound 2000 1₂ 4 5 6 7 2 Xo X₂ " 4₂ = t₂ = +3 118 +3.5 (600) +1.5 +2 (600. +3.5 (1800) +3 +1 2000-