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2. The in-plane bending stiffness is EI and the effective length of column for various end conditions is shown in the fo

Posted: Fri May 27, 2022 7:08 am
by answerhappygod
2 The In Plane Bending Stiffness Is Ei And The Effective Length Of Column For Various End Conditions Is Shown In The Fo 1
2 The In Plane Bending Stiffness Is Ei And The Effective Length Of Column For Various End Conditions Is Shown In The Fo 1 (232.98 KiB) Viewed 35 times
2 The In Plane Bending Stiffness Is Ei And The Effective Length Of Column For Various End Conditions Is Shown In The Fo 2
2 The In Plane Bending Stiffness Is Ei And The Effective Length Of Column For Various End Conditions Is Shown In The Fo 2 (196.65 KiB) Viewed 35 times
ONLY ANSWER PARTS 2 AND 3, DO NOT ANSWER PART 1
2. The in-plane bending stiffness is EI and the effective length of column for various end conditions is shown in the following Figure. (12 points) (a) One fixed end, one free end (b) Both ends pinned (c) One fixed end, one pinned end (d) Both ends fixed L 4071 Le = 0.7L Le = 2L L Le = 0.5L B 1) For columns (a) and (b) shown in the following Figure, determine: (4 points) P P tr L a b I) For column (a), when the P is large enough, will the in-plane buckling occur? (Yes/No) If yes, the minimum critical force Per II) For column (b), when the P is large enough, will the in-plane buckling occur? (Yes/No) If yes, the minimum critical force Per
2) For problems (c) and (d) in the following Figures, determine the minimum critical force Per of in-plane buckling and draw a schematic buckling curve at the minimum critical force Pcr. (8 points) P↓ P↓ L/2 L/2 ## L/2 IT T C 3. 1) The rigid bar is supported by two springs of the same stiffness k and is subjected to an axial compressive force P at its two ends. Knowing that the compressive load P remains horizontal, determine the magnitude of the critical load Per at which the system buckles. (4 points) cr Before buckling After buckling -P P- L/2 L/2 L/2 L/2 2) If the load P is tensile force, will the system buckle? (2 points) and why? (2 points) P- 00000000 L/2 L/2 L/2 00000000 000000000