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Problem for Practice The equation of the turning moment diagram for the three crank engine is given by: T(N-m) = 25000 7
Posted: Fri May 27, 2022 6:59 am
by answerhappygod
- Problem For Practice The Equation Of The Turning Moment Diagram For The Three Crank Engine Is Given By T N M 25000 7 1 (595.9 KiB) Viewed 33 times
Problem for Practice The equation of the turning moment diagram for the three crank engine is given by: T(N-m) = 25000 7500 sin 30 where radians is the crank angle from inner dead centre. The moment of inertia of the flywheel is 400 kg-m² and the mean engine speed is 300 r.p.m. Calculate: (1) the power of the engine, and (ii) the total fluctuation of speed of the flywheel, if (a) the resisting torque is constant, and (b) the resisting torque is (25000 + 3600 sin 0) N-m. [Hint: Since the torque equation is a function of 30 the cycle will be repeated after every 120° (or 2π/3 rad) of the crank rotation] [Check your answers: (1) 785.5 kW; (ii) (a) 1.266% & (b) 0.478%]