Exhaust gases from a water tube boiler at the rate of 0.05 m^3/sec has the following volumetric analysis: CO2 = 13.7%; H

Post by **answerhappygod** » Thu May 26, 2022 11:25 am

: Exhaust Gases From A Water Tube Boiler At The Rate Of 0 05 M 3 Sec Has The Following Volumetric Analysis Co2 13 7 H 1 (60.04 KiB) Viewed 47 times

To find:
11. Determine the Molecular weight of the products in kg/kgm.
12. Determine the gas constant of the products in KJ/kg-K.
13. Determine the specific heat Cp of the products in KJ/kg-K.
14. Determine the specific heat Cv in KJ/kg-K.
15. Determine the Adiabatic Power of the blower in kw
16. Determine the isothermal power of the blower in kw.
Please provide clear and orderly solution. I need it ASAP. I will rate. Thank you.
Exhaust gases from a water tube boiler at the rate of 0.05 m^3/sec has the following volumetric analysis: CO2 = 13.7%; H2O = 5.8%; SO2 = 0.2%; O2 = 4% and N2 = 76.2%. Pressure and temperature are 100 KPa and 150 C, respectively. This gases is driven by a low speed blower to the smokestack to a pressure of 250 kPa.