- Problem 27 72 The Low And S The Foor By 0 0040 Ga Figure Thom Nours Is Shaded To Ninge At Pin P Dhe Me 180 Cand A Unum 1 (20.47 KiB) Viewed 23 times
- Problem 27 72 The Low And S The Foor By 0 0040 Ga Figure Thom Nours Is Shaded To Ninge At Pin P Dhe Me 180 Cand A Unum 2 (35.01 KiB) Viewed 23 times
- Problem 27 72 The Low And S The Foor By 0 0040 Ga Figure Thom Nours Is Shaded To Ninge At Pin P Dhe Me 180 Cand A Unum 3 (35.01 KiB) Viewed 23 times
- Problem 27 72 The Low And S The Foor By 0 0040 Ga Figure Thom Nours Is Shaded To Ninge At Pin P Dhe Me 180 Cand A Unum 4 (30.86 KiB) Viewed 23 times
Problem 27.72 The lower end of the thin uniform rod in (Figure 1) is attached to the floor by a frictionless hinge at point P. The rod has mass 0.0840 kg and length 18.0 cm and is in a uniform magnetic field 0.180 T that is directed into the page. The rod is held at an angle 54,0 above the horizontal by a horizontal string that connects the top of the rod to the wall. The rod carries a current 12.0 A in the direction toward P. Figure 1 of 1 P X X 0 TRO B
Y Part A Calculate the tension in the string. Use the fact that IBL for a uniform bar of length L carring a current I in a magnetic field B. Express your answer with the appropriate units. μA C End T= 0.472 N Submit Previous Answers Bequest Answer x Incorrect; Try Again; 4 attempts remaining Constants Next >