The circuit in Figure 13 operates at frequencyin steady state condition. The phasor of the input voltage, Vs is , a

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answerhappygod
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The circuit in Figure 13 operates at frequencyin steady state condition. The phasor of the input voltage, Vs is , a

Post by answerhappygod »

The circuit in Figure 13 operates at frequencyin steady state condition. The
phasor of the input voltage,
Vs is , and
k=0.6.
a) Find and draw the Norton equivalent circuit seen between
terminals a and b.
b) Find the optimal value of the
impedance ZL so that the maximum
power is transferred to the load, then find the maximum delivered
power to the load and draw the circuit with the derived values of
the Norton equivalent circuit (from part a) and the
optimal ZL .
c) Now the sinusoidal voltage source is disconnected from the
circuit in Figure 13 and replaced with a constant voltage source of
amplitude 12 Volts, in series with a switch (see Figure 14).
Initial energy of the circuit is zero. The switch is closed at t=0.
Construct the s-domain equivalent of the circuit in Figure 13, and
find the s-domain expression for the Norton equivalent circuit
between terminals a and b.
The Circuit In Figure 13 Operates At Frequencyin Steady State Condition The Phasor Of The Input Voltage Vs Is A 1
The Circuit In Figure 13 Operates At Frequencyin Steady State Condition The Phasor Of The Input Voltage Vs Is A 1 (68.59 KiB) Viewed 10 times
+1 V₂ Figure 13 10Ω j4 a kl Z₁ b Norton Equivalent

+1 Vs Figure 14 t=0 10Ω I j4 а ZL kl b Norton Equivalent
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