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200 kV photons in an incident beam will be attenuated by 1.5 mm of lead barrier. If there are 250,000 photons in the said beam.... How much photons will be left after it passes through the lead barrier. Show all solutions (5 points) TABLE 3.3b Linear attenuation coefficients of selected elements, cm-¹. Energy, Chromium Cobalt Copper Iron Magnesium Lead (Z = 82) Manganese (Z = 25) KV (Z = 24) (Z = 27) (Z = 29) (Z = 26) (Z = 12) 50 11.0 18.8 22.9 15.2 65.0 0.561 12.6 100 2.29 3.53 4.10 2.93 62.0 0.292 150 1.29 1.80 1.98 1.54 21.8 0.242 200 0.992 1.32 1.39 1.15 10.7 0.216 300 0.769 0.970 0.997 0.866 4.29 0.186 400 0.662 0.827 0.837 0.740 2.49 0.165 500 0.150 0.740 0.742 0.662 0.525 0.524 0.524 0.471 1.72 0.471 0.798 0.109 0.595 1000 0.426 2000 0.302 4000 0.232 0.291 0.374 0.374 0.334 0.524 0.0768 0.295 0.260 0.484 0.0548 0.0467 0.0399 6000 0.212 0.271 0.277 0.239 0.505 10000 0.202 0.264 0.272 0.233 0.570 15000 0.209 0.275 0.285 0.241 0.643 30000 0.231 0.311 0.327 0.270 0.807 0.0374 0.0369 2.52 1.36 1.03 0.788 0.679 0.608 0.435 0.309 0.238 0.219 0.211 0.217 0.243