Decide on the FS expression Which time domain signal is represented by the following FS coefficients? Leverage FS proper
Posted: Mon May 23, 2022 10:12 am
Decide on the FS expression
Which time domain signal is represented by the following FS
coefficients?
Leverage FS properties
(a) r(t)=2sin (27-3)+sin (6) (b) X(t) cos(pt) mmm. t -3 -2 -11 1 2 3 1 2 2 (c) X(t) ... ДАМА, 0 + 2 -2 3 1 2
= (a) X[k] = - jg[k-2] + jg[k+2] + 28 [k- 3] + 28 (k+3], wo = |X[k] 9id k 4 -2 0 2 4 6 arg{X[k]} 2p р 2 4 k 4 -2 0 -р (b) = W = 277 -2p
7 FS: W= 6. xt) - X[k] =- k2-k! (a) y(t) = x(3) (b) y(t) = cos(47t).r(t) (c) y(t) = x(t) r(t-1)
7.x[n] = sin (11/20) FS:2 = 7/10 + X[k] sin (in/20) (a) Y[k] = X[k-5] + X[k+5] (b) Y[k] = cos(km/5)X[k] (c) Y[k] = X[k] ⓇX[k]
Which time domain signal is represented by the following FS
coefficients?
Leverage FS properties
(a) r(t)=2sin (27-3)+sin (6) (b) X(t) cos(pt) mmm. t -3 -2 -11 1 2 3 1 2 2 (c) X(t) ... ДАМА, 0 + 2 -2 3 1 2
= (a) X[k] = - jg[k-2] + jg[k+2] + 28 [k- 3] + 28 (k+3], wo = |X[k] 9id k 4 -2 0 2 4 6 arg{X[k]} 2p р 2 4 k 4 -2 0 -р (b) = W = 277 -2p
7 FS: W= 6. xt) - X[k] =- k2-k! (a) y(t) = x(3) (b) y(t) = cos(47t).r(t) (c) y(t) = x(t) r(t-1)
7.x[n] = sin (11/20) FS:2 = 7/10 + X[k] sin (in/20) (a) Y[k] = X[k-5] + X[k+5] (b) Y[k] = cos(km/5)X[k] (c) Y[k] = X[k] ⓇX[k]