How do you get that for question a the E= Ered -Eoxd = 0,2680v - 0,2222v. Are those values taken from a table or calcul
Posted: Mon May 23, 2022 7:06 am
How do you get that for question a the E= Ered -Eoxd
= 0,2680v - 0,2222v. Are those values taken from a table or
calculated? Please explain.
Consider the following cell, at 25 ° C and 1 bar:
Pt, Ag / AgCl (s) | HCl (aq) | Hg2Cl2 (s), Pt
For this cell:
a) calculate EMS if mHCl = 0.100 mol / kg. (m is
molality)
b) calculate EMS if mHCl = 1,000 mol / kg.
= 0,2680v - 0,2222v. Are those values taken from a table or
calculated? Please explain.
Consider the following cell, at 25 ° C and 1 bar:
Pt, Ag / AgCl (s) | HCl (aq) | Hg2Cl2 (s), Pt
For this cell:
a) calculate EMS if mHCl = 0.100 mol / kg. (m is
molality)
b) calculate EMS if mHCl = 1,000 mol / kg.