Salicylaldehyde reacts with diethyl zinc in a 1:1 ratio to form compound A according to the following scheme: OH O + Et₂
Posted: Mon May 23, 2022 6:07 am
Salicylaldehyde reacts with diethyl zinc in a 1:1 ratio to form compound A according to the following scheme:
OH O
+ Et₂Zn
A
+
gas
On cooling, compound B crystallises from solution, and half an equivalent of diethyl zinc is found to have reformed in solution.
A
B + 0.5 Et₂Zn
d. Identify A, B, and the gas.
e. By what process does A transform to B? Sketch a plausible intermediate.
f. A reacts cleanly with anhydrous HCI to release a gas and form compound
I need its urgent.
C. Identify C, and explain why this is the sole product.
Question continues on next page
g. A reacts cleanly with Me,SiCl to form compound D, with molecular weight 194, a colourless crystalline solid, E, and reform some Et Zn. Identify D and E using the available data, and explain why this is the sole product.
OH O
+ Et₂Zn
A
+
gas
On cooling, compound B crystallises from solution, and half an equivalent of diethyl zinc is found to have reformed in solution.
A
B + 0.5 Et₂Zn
d. Identify A, B, and the gas.
e. By what process does A transform to B? Sketch a plausible intermediate.
f. A reacts cleanly with anhydrous HCI to release a gas and form compound
I need its urgent.
C. Identify C, and explain why this is the sole product.
Question continues on next page
g. A reacts cleanly with Me,SiCl to form compound D, with molecular weight 194, a colourless crystalline solid, E, and reform some Et Zn. Identify D and E using the available data, and explain why this is the sole product.