Consider a solution made by dissolving 342 g of sucrose in 127 ml of water at 45oC. The vapor pressure of water at 450℃
Posted: Sun May 22, 2022 11:57 pm
Consider a solution made by dissolving 342 g of sucrose in 127 ml of water at 45oC. The vapor pressure of water at 450℃ is 0.095 atm and the density of water at 450C is 0.992 g/ml. What is the vapor pressure of the sucrose/water solution? (Note: The molar mass of sucrose is 180.2 g/mol.) (1 Point) O a. 0.075 atm O b. 0.115 atm O c.0.224 atm O d. 0.008 atm
The vapor pressure of pure liquid toluene at 300 K is P* = 3.572 kPa, and the vapor pressure of pure liquid benzene at 300 K is P* = 9.657 kPa. Assuming that mixtures of toluene and benzene behave as ideal solutions, what will be the total vapor pressure (PT) of a toluene- benzene mixture containing 0.60 mole-fraction of toluene at a temperature of 300 K, and what will be the mole-fraction of toluene (Xtoluene) in the vapor over this mixture? (1 Point) a. PT = 7.219 kPa; Xtoluene = 0.643 (in vapor) b. PT = 6.006 kPa: Xtoluene = 0.643 (in vapor) c. PT = 6.006 kPa: Xtoluene = 0.357 (in vapor) Od. There is not enough information provided to answer this question.
The vapor pressure of pure liquid toluene at 300 K is P* = 3.572 kPa, and the vapor pressure of pure liquid benzene at 300 K is P* = 9.657 kPa. Assuming that mixtures of toluene and benzene behave as ideal solutions, what will be the total vapor pressure (PT) of a toluene- benzene mixture containing 0.60 mole-fraction of toluene at a temperature of 300 K, and what will be the mole-fraction of toluene (Xtoluene) in the vapor over this mixture? (1 Point) a. PT = 7.219 kPa; Xtoluene = 0.643 (in vapor) b. PT = 6.006 kPa: Xtoluene = 0.643 (in vapor) c. PT = 6.006 kPa: Xtoluene = 0.357 (in vapor) Od. There is not enough information provided to answer this question.