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Posted: **Sun May 22, 2022 11:54 pm**

: 1a H2a He Li Be Cnof Ne Na Mg 38 48 58 68 79 Aisip S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Z 1 (28.71 KiB) Viewed 15 times

: 1a H2a He Li Be Cnof Ne Na Mg 38 48 58 68 79 Aisip S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Z 2 (40.32 KiB) Viewed 15 times

: 1a H2a He Li Be Cnof Ne Na Mg 38 48 58 68 79 Aisip S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Z 3 (22.95 KiB) Viewed 15 times

: 1a H2a He Li Be Cnof Ne Na Mg 38 48 58 68 79 Aisip S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Z 4 (42.89 KiB) Viewed 15 times

: 1a H2a He Li Be Cnof Ne Na Mg 38 48 58 68 79 Aisip S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Z 5 (23.18 KiB) Viewed 15 times

1A H2A He Li Be CNOF Ne Na Mg 38 48 58 68 79 AISIP S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe Pb Bi Po At Rn Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Fr Ra Rc Rf Ha Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No When rubidium reacts with chlorine to form an ionic compound, each metal atom loses nonmetal atom gains electron(s). There must be rubidium atom(s) for every chlorine atom(s) in the reaction. Enter the smallest integers possible. electron(s) and each

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