7. The equilibrium constant K, for the following reaction is K. = 4.8 x 10¹0 H2(g) + Cl2(g) ← 2 HCl(Ⓡ) Calculate K, valu
Posted: Sun May 22, 2022 11:01 pm
7. The equilibrium constant K, for the following reaction is K. = 4.8 x 10¹0 H2(g) + Cl2(g) ← 2 HCl(Ⓡ) Calculate K, values for: a) 1/2 H2₂(g) + 1/2 Cl2(g) HCK=√481010 2.19+105 b) 2 HCl + + H₂ + Cl₂ Kc = 4,8x10²0 = 2,08×10="/