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Question 1 Copper forms two complexes with acetate: Question la Cu²+ + CH3CO₂ = Cu(CH3CO₂)* Cu²+ + 2 CH3CO₂ Cu(CH3CO2)2
Posted: Sun May 22, 2022 10:18 pm
by answerhappygod
- Question 1 Copper Forms Two Complexes With Acetate Question La Cu Ch3co Cu Ch3co Cu 2 Ch3co Cu Ch3co2 2 1 (44.79 KiB) Viewed 15 times
Question 1 Copper forms two complexes with acetate:
Question la Cu²+ + CH3CO₂ = Cu(CH3CO₂)* Cu²+ + 2 CH3CO₂ Cu(CH3CO2)2 Cu(CH3CO₂) + CH3CO₂ Cu(CH3CO2)2 Evaluate
Question 1b Consider 1.00 L of solution prepared by mixing 1.00 x 104 mol Cu(CIO4)2 and 0.100 mol of sodium acetate. Find the fraction of copper in the form Cu²+. Evaluate Find K₂ for the reaction b₁ = 1.69 x 10² b₂ = 4.26 x 10³