Given the equation below, how many grams of PCI5 are needed to react with 75 g of CH3OH? 2 CH3OH + PC15 → 2 CH3CI + 2 PO
Posted: Sun May 22, 2022 10:16 pm
Given the equation below, how many grams of PCI5 are needed to react with 75 g of CH3OH? 2 CH3OH + PC15 → 2 CH3CI + 2 POCI3 + H₂O molar masses: CH3OH: 32.05 g/mol PCI 5: 208.22 g/mol CH3CI: 50.49 g/mol POCI3: 153.32 g/mol H₂O: 18.02 g/mol