Given the equation below, how many grams of PCls are needed to react with 75 g of CH3OH? 2 CH3OH + PC15 – 2 CH3CI + 2 PO
Posted: Sun May 22, 2022 8:39 pm
Given the equation below, how many grams of PCls are needed to react with 75 g of CH3OH? 2 CH3OH + PC15 – 2 CH3CI + 2 POCI; + H2O molar masses: CH3OH: 32.05 g/mol PC15: 208.22 g/mol CH3Cl: 50.49 g/mol POC13: 153.32 g/mol H20: 18.02 g/mol