2. Determine the theoretical yield of solid lead(II) iodide (Molar Mass = 4610 g/mol) when 15.3 mL of a 0.063 M Pb(NO3),
Posted: Sun May 22, 2022 6:46 pm
2. Determine the theoretical yield of solid lead(II) iodide (Molar Mass = 4610 g/mol) when 15.3 mL of a 0.063 M Pb(NO3), solution and 21.5 mL of a 0.079 M Kl solution combine. Pb(NO3)2(aq) + 2Kl(aq) → 2KNO,(aq) + Pbla(s) balanced a. b. c. d. 0.78 g Pbl(s) 0.39 g Pbl;(s) 0.22 g Pbl(s) 1.6 g Pbl(s) 0.44 g Pbl(s) e.