In the chemistry lab, they are trying to make a galvanic (voltaic) cell. Given that they are using the two half-reaction
Posted: Sun May 22, 2022 4:38 pm
In the chemistry lab, they are trying to make a galvanic
(voltaic) cell. Given that they are using the two half-reactions
below at standard conditions to make the cell, what species are
produced at each electrode? What would the potential be for the
cell?
E° (volts)
Ag +(aq) + e- ⟶ Ag(s). 0.80
Ni2+ (aq) + 2 e- ⟶ Ni (s) - 0.23
The hemoglobin molecule carries O2 in the blood from the lungs
to the cells, where the O2 is released for metabolic processes. The
molecule can be represented as Hb in its unoxygenated form and as
Hb.O2 in its oxygenated form. One reason CO is toxic is that it
competes with O2 for binding to Hb:
Hb.O2(aq) + CO(g) ⟺ Hb.CO(aq) +
O2(aq)
Δ G° = -14 kJ at 37°C (body temperature)
What is the ratio of [Hb.CO]/[Hb.O2] at 37 °C with [O2] = [CO]?
(voltaic) cell. Given that they are using the two half-reactions
below at standard conditions to make the cell, what species are
produced at each electrode? What would the potential be for the
cell?
E° (volts)
Ag +(aq) + e- ⟶ Ag(s). 0.80
Ni2+ (aq) + 2 e- ⟶ Ni (s) - 0.23
The hemoglobin molecule carries O2 in the blood from the lungs
to the cells, where the O2 is released for metabolic processes. The
molecule can be represented as Hb in its unoxygenated form and as
Hb.O2 in its oxygenated form. One reason CO is toxic is that it
competes with O2 for binding to Hb:
Hb.O2(aq) + CO(g) ⟺ Hb.CO(aq) +
O2(aq)
Δ G° = -14 kJ at 37°C (body temperature)
What is the ratio of [Hb.CO]/[Hb.O2] at 37 °C with [O2] = [CO]?