Calculate the entropy change corresponding to the process of vaporization of 1 mol of liquid water at 0 C and 1 atm into
Posted: Sun May 22, 2022 3:46 pm
Calculate the entropy change corresponding to the process of
vaporization of 1 mol of liquid water at 0 C and 1 atm into steam
at 100 C if the process is carried out
a) irreversibly by the following path: 0 C, 1 atm water → 100 C,
1 atm water → 100 C, 1 atm steam
b) reversibly by the following path: 0 C, 1 atm water →0 C, P
vapour water →0 C, Pvapour steam →100 C, Pvapour steam
→100 C, 1 atm steam
(∆vapHm,373K=40,67 kJ/mol; ∆vapHm,273K=44,92 kJ/mol; vapor
pressure of water at 0oC is Pvap=4,58 mmHg; Cp,m,water=75,5
J/mol.K; Cp,m,steam=33,8 J/mol.K)
Calculate the entropy change corresponding to the process of vaporization of 1 mol of liquid water at 0°C and 1 atm into steam at 100°C if the process is carried out a) irreversibly by the following path: 0°C. I arm water - 100°C, I arm water -- 100°C / arm steam b) reversibly by the following path: 0°C. I atm water -0°C. Puhar water--(C. Power Steam -+100°C. Pakar Steam -100°C, I am steamt (AvupHm.373 40,67 kJ/mol; AvapH.273-44,92 kJ/mol; vapor pressure of water at 0°C is Pap-4,58 mmHg; Cp.m.water 75,5J/mol.K: Cp.m.steam-33,8 J/mol.K)
vaporization of 1 mol of liquid water at 0 C and 1 atm into steam
at 100 C if the process is carried out
a) irreversibly by the following path: 0 C, 1 atm water → 100 C,
1 atm water → 100 C, 1 atm steam
b) reversibly by the following path: 0 C, 1 atm water →0 C, P
vapour water →0 C, Pvapour steam →100 C, Pvapour steam
→100 C, 1 atm steam
(∆vapHm,373K=40,67 kJ/mol; ∆vapHm,273K=44,92 kJ/mol; vapor
pressure of water at 0oC is Pvap=4,58 mmHg; Cp,m,water=75,5
J/mol.K; Cp,m,steam=33,8 J/mol.K)
Calculate the entropy change corresponding to the process of vaporization of 1 mol of liquid water at 0°C and 1 atm into steam at 100°C if the process is carried out a) irreversibly by the following path: 0°C. I arm water - 100°C, I arm water -- 100°C / arm steam b) reversibly by the following path: 0°C. I atm water -0°C. Puhar water--(C. Power Steam -+100°C. Pakar Steam -100°C, I am steamt (AvupHm.373 40,67 kJ/mol; AvapH.273-44,92 kJ/mol; vapor pressure of water at 0°C is Pap-4,58 mmHg; Cp.m.water 75,5J/mol.K: Cp.m.steam-33,8 J/mol.K)