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A proton moving in a uniform magnetic field with V₁ = 1.06 x 106 m/s experiences force F₁ = 1.31 x10-16 N. A second prot
Posted: Sun May 22, 2022 1:47 pm
by answerhappygod
- A Proton Moving In A Uniform Magnetic Field With V 1 06 X 106 M S Experiences Force F 1 31 X10 16 N A Second Prot 1 (37.22 KiB) Viewed 10 times
A proton moving in a uniform magnetic field with V₁ = 1.06 x 106 m/s experiences force F₁ = 1.31 x10-16 N. A second proton with v₂ =2.30 ×106 m/s experiences F₂3.51 x10-16 N in the same field. Part A What is the magnitude of B? Express your answer with the appropriate units. ► View Available Hint(s) I μA ? Units Part B What is the direction of B? Give your answer as an angle measured ccw from the +x-axis. Express your answer in degrees. ► View Available Hint(s) ΠΙ ΑΣΦ ? 0 = B= Submit Value