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An electron enters a perpendicular magnetic field with unknown magnitude strength. The electron has initial velocity v =

Posted: Sun May 22, 2022 1:34 pm
by answerhappygod
An electron enters a perpendicular magnetic field with unknown
magnitude strength. The electron has initial velocity v = 3*10^6
m/sec and moves from right to left. The force acting on an electron
is measured to be |F| = 10^-9 N. If the electron was deflected
upward.
a. What direction does the magnetic field point? (Draw a
picture)
b. Calculate the magnitude of the magnetic field?