A mixture of 0.178 mol of NH3, 0.544 mol of N2 and 0.708 mol of H2 is allowed to reach equilibrium. 2NH3(9) - N2(g) + 3
Posted: Wed Nov 24, 2021 10:39 am
- A Mixture Of 0 178 Mol Of Nh3 0 544 Mol Of N2 And 0 708 Mol Of H2 Is Allowed To Reach Equilibrium 2nh3 9 N2 G 3 1 (7.16 KiB) Viewed 87 times
equilibrium? (Answer to the nearest 0.001 mol and include the
unit.)
2. How many moles of NH3 are present at
equilibrium? (Answer to the nearest 0.001 mol and include the
unit.)
A mixture of 0.178 mol of NH3, 0.544 mol of N2 and 0.708 mol of H2 is allowed to reach equilibrium. 2NH3(9) - N2(g) + 3 H2(g) - Suppose that, at equilibrium, it is found that 0.496 mol of N2 is present.