Page 1 of 1

MODULE 2 LESSON 4 LAB 1. A ball is launched from the ground with a velocity of 20.0 m/s at an angle of 60.0° from the ho

Posted: Sun May 22, 2022 9:23 am
by answerhappygod
Module 2 Lesson 4 Lab 1 A Ball Is Launched From The Ground With A Velocity Of 20 0 M S At An Angle Of 60 0 From The Ho 1
Module 2 Lesson 4 Lab 1 A Ball Is Launched From The Ground With A Velocity Of 20 0 M S At An Angle Of 60 0 From The Ho 1 (30.71 KiB) Viewed 13 times
Module 2 Lesson 4 Lab 1 A Ball Is Launched From The Ground With A Velocity Of 20 0 M S At An Angle Of 60 0 From The Ho 2
Module 2 Lesson 4 Lab 1 A Ball Is Launched From The Ground With A Velocity Of 20 0 M S At An Angle Of 60 0 From The Ho 2 (46.69 KiB) Viewed 13 times
Module 2 Lesson 4 Lab 1 A Ball Is Launched From The Ground With A Velocity Of 20 0 M S At An Angle Of 60 0 From The Ho 3
Module 2 Lesson 4 Lab 1 A Ball Is Launched From The Ground With A Velocity Of 20 0 M S At An Angle Of 60 0 From The Ho 3 (17.91 KiB) Viewed 13 times
Module 2 Lesson 4 Lab 1 A Ball Is Launched From The Ground With A Velocity Of 20 0 M S At An Angle Of 60 0 From The Ho 4
Module 2 Lesson 4 Lab 1 A Ball Is Launched From The Ground With A Velocity Of 20 0 M S At An Angle Of 60 0 From The Ho 4 (23.25 KiB) Viewed 13 times
Module 2 Lesson 4 Lab 1 A Ball Is Launched From The Ground With A Velocity Of 20 0 M S At An Angle Of 60 0 From The Ho 5
Module 2 Lesson 4 Lab 1 A Ball Is Launched From The Ground With A Velocity Of 20 0 M S At An Angle Of 60 0 From The Ho 5 (20.69 KiB) Viewed 13 times
MODULE 2 LESSON 4 LAB 1. A ball is launched from the ground with a velocity of 20.0 m/s at an angle of 60.0° from the horizontal as shown, calculate the initial horizontal (X) and vertical (Y) components of the velocity. (3 marks for Vx, 3 marks for Vy) 20.0m/s Y 60.0° I X ANSWER:

As the ball moved through the air in its projectile path, the following data was collected for the horizontal (Vx) and vertical (Vy) velocities: Table 1:Horizontal Data Table 2: Vertical Data t(s) Vx (m/s) t(s) Vy (m/s) 0.0 10.0 0.0 17.3 0.5 10.0 0.5 12.4 1.0 10.0 1.0 7.5 1.5 10.0 1.5 2.6 2.0 10.0 2.0 -2.3 2.5 10.0 2.5 -7.2 3.0 10.0 3.0 - 12.1 3.5 10.0 3.5 -17.0 2. Why is the horizontal velocity not changing as time goes by? (1 mark) ANSWER:

3. Why is the vertical velocity changing as time goes by? (1 mark) ANSWER:

4. Plot vertical velocity (V) versus time on a graph. Be sure to give it a title and label each axis with the variable and unit. Graphs must be done on grid paper or using technology. (You can plot the graph on paper and then paste a photo of it here). (4 marks) ANSWER:

5. Calculate the slope of the line for the vertical velocity-time graph. Include the units for velocity and time, and correct significant digits. What variable is the slope equivalent to? (3 marks)