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Question 1 Not yet answered Marked out of 20.00 [20 points) An optical fiber consists of a core made of flint glass (ncore = 1.67) surrounded by a cladding made of crown glass (ncladding = 1.53 ). A ray of light in the air enters the fiber at an angle 01 with respect to the normal, it passes through the core and hits the core cladding interface with c (critical angle) to produce a total internal reflection at the core-cladding interface as shown in the following figure. P Flag question Cladding Air Core e. A. [5 points) Find the critical angle 8c for the core-cladding interface. oc- B. [5 points] If c = 67°, calculate the angle 82. 02 = C. [1 point] Using the formula sheet, which formula can be used to calculate the angle of incidence ? 1 sin-1 D. [1 point] If 02 = 22, the angle of incidence @ will be given by: 1.53xsin(22) 1xsin(22) sin Osin 1.67xsin (22) 1.53 1 E. [3 points) If 02 = 22°, calculate the angle of incidence 01 0 F. [5 points) If the angle of incidence 01 = 53, will the ray of light undergo total internal reflection at the core-cladding interface? ONo OYes