Answer Happy

[20 points) An optical fiber consists of a core made of flint glass (ncore = 1.64) surrounded by a cladding made of crown glass (ncladding = 1.51). A ray of light in the air enters the fiber at an angle 0, with respect to the normal, it passes through the core and hits the core cladding interface with 0. (critical angle) to produce a total internal reflection at the core-cladding interface as shown in the following figure. Cladding Air Core 82 0 A. [5 points) Find the critical angle 0, for the core-cladding interface. 0. = B. [5 points) If 8. = 68, calculate the angle 02. 02 = C. [1 point] Using the formula sheet, which formula can be used to calculate the angle of incidence 0,? D. [1 point] If 02 = 21', the angle of incidence , will be given by: Osin' (1.64xsin_21) -) Osin! ( 1Sixsin(21) - E. [3 points) If 02 = 21°, calculate the angle of incidence , -1 ( Osin! ( ixsin(21) 1.51 F. [5 points) If the angle of incidence 0; = 51, will the ray of light undergo total internal reflection at the core-cladding interface?