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A 0.137-kg particle undergoes simple harmonic motion along the horizontal X-axis between the points x3 = -0.281 m and x2

Posted: Sun May 22, 2022 6:55 am
by answerhappygod
A 0 137 Kg Particle Undergoes Simple Harmonic Motion Along The Horizontal X Axis Between The Points X3 0 281 M And X2 1
A 0 137 Kg Particle Undergoes Simple Harmonic Motion Along The Horizontal X Axis Between The Points X3 0 281 M And X2 1 (25.07 KiB) Viewed 24 times
A 0.137-kg particle undergoes simple harmonic motion along the horizontal X-axis between the points x3 = -0.281 m and x2 = 0.427m. The period of oscillation is 0.667 s. Find the frequency, S, the equilibrium position, Xey, the amplitude, A, the maximum speed, Umes, the maximum magnitude of acceleration, Amas, the force constant, k, and the total mechanical energy, E = Hz m X A m m Umax m/s m/s? k N/m E J