hint: start with fundamental equation for thermodynamics (i) Derive an expression for the change in Gibbs energy of vapo
Posted: Sat May 21, 2022 5:00 pm
hint: start with fundamental equation for thermodynamics
(i) Derive an expression for the change in Gibbs energy of
vaporisation with temperature for water (you may assume a constant
pressure of 1 bar). Thus calculate the temperature at which
vaporisation becomes thermodynamically favourable and comment on
the accuracy of this calculation. [2 marks]
(ii) Derive an expression for the change in Gibbs energy of
vaporisation with pressure for water (you may assume a constant
temperature of 298.15 K). Thus calculate the pressure at which
vaporisation becomes thermodynamically favourable.
All data refer to 298.15 K and 1 bar pressure. Units of AH and AG° are ki mol-'; Units of S and Cp are J K-1 mol-1 1 Compound AH AG S° Water Water vapour H2O H2O(9) -285.8 -241.8 -2371 ...228.6 69.9 188.3 75.3 33.6
- Hint Start With Fundamental Equation For Thermodynamics I Derive An Expression For The Change In Gibbs Energy Of Vapo 1 (200.85 KiB) Viewed 12 times
vaporisation with temperature for water (you may assume a constant
pressure of 1 bar). Thus calculate the temperature at which
vaporisation becomes thermodynamically favourable and comment on
the accuracy of this calculation. [2 marks]
(ii) Derive an expression for the change in Gibbs energy of
vaporisation with pressure for water (you may assume a constant
temperature of 298.15 K). Thus calculate the pressure at which
vaporisation becomes thermodynamically favourable.
All data refer to 298.15 K and 1 bar pressure. Units of AH and AG° are ki mol-'; Units of S and Cp are J K-1 mol-1 1 Compound AH AG S° Water Water vapour H2O H2O(9) -285.8 -241.8 -2371 ...228.6 69.9 188.3 75.3 33.6