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3. The enthalpy of triethylamine-benzene solutions at 298.15 K are given by: AmirH =IB(1 - IB)[A + B(1 – 2.0B)] J/mol wh
Posted: Sat May 21, 2022 4:14 pm
by answerhappygod
- 3 The Enthalpy Of Triethylamine Benzene Solutions At 298 15 K Are Given By Amirh Ib 1 Ib A B 1 2 0b J Mol Wh 1 (86.33 KiB) Viewed 12 times
3. The enthalpy of triethylamine-benzene
solutions at 298.15 K are given by: AmirH =IB(1 - IB)[A + B(1 – 2.0B)] J/mol where A= 1418 J/mol and B= -482.4 J/mol where TB is the mole fraction of benzene. (a) Develop expressions for (HB-HB) and (HEA - HEA) (b) Compute values for (HB-HB) and (HEA-HEA) at IB = 0.5 (c) One mole of a 25 mol % benzene mixture is to be mixed with one mole of a 75 mol % benzene mixture at 298.15 K. How much heat must be added or removed for the processed to be isothermal?