Answer Happy

a) The first-order, liquid-phase, exothermic reaction A → B takes place in a batch reactor. At t=0 h, all the reactant A is present in the reactor (no B present) at the required reaction temperature and the reaction is initiated by adding a small amount of catalyst. At t=0 h, an inert coolant flow to the reactor is initiated to control the reaction temperature. The reaction temperature is kept constant at 400 K, by varying the flowrate of the coolant. The coolant C temperature is 390 K. i) Calculate the flowrate of the coolant (in kg s-l) at the start of the reaction (t = 0 h) [7] ii) Calculate the flowrate of the coolant (in kg s l) at t= 2 h after the reaction started [3] iii) When is the coolant flowrate higher (at t=0 h or t = 2 h) and why? [3] iv) How would the results change if the reaction was not first order? [2]