Answer Happy

Problems 2 and 3 refer to the floor plan shown in Fig. 2. S CI C2 C3 C4 CS 3 GI (typ.) C6 C7 C8 Given: L = 25' (typ.) and S = 10 (typ.). So, the overall floor plan = 75' x 60' The beam width (bw) and depth (h) of B1 (typ.) are taken to be 10-in and 20-in, respectively. L SI (typ B1 (typ.) B1 (typ) C9 cio C11 C12 A typical girder, e.g., G1, has a width (b) of 12-in. GI (typ.) C13 C14 C15 C16 Fig. 2 - Floor Plan for Problems 2 & 3.
Problem 2. The one-way slab, 51 (typ.), has a thickness of 5-in, cast with fo' = 5,000 psi (normal weight concrete, 150 pcf. Bi = 0.8). No. 4 Gr-60 rebars are used as main (i.e., longitudinal) reinforcement, and No. 3 Gr-60 rebars are secondary (i.e., temperature and shrinkage, perpendicular to main) reinforcement, with a standard cover of %-in. No shear reinforcement is provided. The floor is subjected to a live load of 50 psf. (a) (10 points) Draw (hand-drawing is acceptable, for as long as it is clear) the cross-section view (i.e., section A-A), without showing the reinforcement of the slab based on the information provided. Then, compute & show on the same view the required shear forces (V.) and moments (M) at critical locations of the slab per AC1318. Use clear span for your calculations,