Answer Happy

The uniform 939-mm link AB slides up on frictionless rollers as shown below. At the instant shown, the link AB is vertical and the absolute velocity of point A is 15.2 m/s in the direction shown. Ignore the link thickness and roller diametres. For this configuration, θ1=32 degrees and θ2=21 degrees as shown.
Calculate the absolute velocity of the centre of mass at G. Give your answer in the form Z = 2 vGx + vGy in m/s where vGx is the horizontal component of the velocity vector (positive to the right) and vGy is the vertical component of the velocity vector (positive upwards). Round your final answer to two decimal places.
Hint: Find the angular velocity first by considering the velocities of points A and B before solving for the absolute velocity of G.
Answer is 16
don't assume any values
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