오전 12:56 5월 18일 수요일 9 30% 5 T + : Same property as in A Turbo expander 80% efficiency Turbo compressor 80% efficiency A
Posted: Sat May 21, 2022 9:18 am
- 1 (29.73 KiB) Viewed 14 times
- 2 (36.91 KiB) Viewed 14 times
- 3 (43.68 KiB) Viewed 14 times
- 4 (30.6 KiB) Viewed 14 times
오전 12:56 5월 18일 수요일 9 30% < T + : Suggested procedure 1. Get the all known values 2. How much of steam required for current operation without turbo-expander 3. Suggested process - Expander 3-1. Reversible 3-2. 80% efficiency irreversible expander 4. Compressor 4-1. Reversible 4-2. 80% efficiency 4 22 1. Get the all known values
오전 12:56 5월 18일 수요일 9 30% < 5 T + : LUNCH 305 fficiency 130F 1. Get the all known values A. P in the vapor line to condenser is equivalent to 130F = This means that it is saturated condition & 100% vapor (at P = 2.223 psia) (HA, SA) = (?, ?) B. Properties of steam from the boiler: 400 psia, 500 F (Hg, Sg) = (?, ?) C. Properties after the throttle valve: energy balance *Hc = Hg = ? D. Saturated liquid at 10 psig *10 psig = 10 + 14.7 = 24.7 psia * Via interpolation: T = 239.3434 F *From steam table, find that and Hiquid Ho So E 100"F Condenser لوقف 20F Evaporator Throttle 10 P بند 40% solids 60% 1,0 80% solids 11,0 F 5 Sata quid at 10 psis D 22 Summary of what you got H = A He =
오전 12:57 5월 18일 수요일 9 30% 5 T 9 + sar'd liquid at 10 prie D Summary of what you got A HA= H, = В Нp = с на D HD S Sp = = Turbo expander 80 efficiency Same property as in A Turbo compressor 809 efficiency 130-F 100°F Com len 70°F Evaporator Boer Throttle 400-psia stam B 500 F 10 PE ve 40% solide 11,0 solids 203 11,0 E 22 Sat'd liquida 10 pz D w much actoam rored for current aneration without