Below is my question The pictures below are my answer. I want you to correct my answer.
Posted: Sat May 21, 2022 8:50 am
Below is my question
The pictures below are my answer. I want you to
correct my answer.
1X1 mi m = m = Assumed parameter values kg - sprung mass kg - unsprung mass k= N/m k = N/m N/m F(t) = N F(t) CE m2 x:(t) find the following a. The differential equations of motion. b. The transient and steady state responses. c. The natural frequencies and mode shapes d. Check if the system can be decoupled or not only check!). Write the differential equations of motion, the transient and steady state responses, the natural frequencies, and the mode shapes (from part " 42, 46, 4c" above) by substitute with the actual values of the parameters K1, K2, CI, MI, M2, etc. and reasonable values for FO and c.
Car suspension Model F Free body diagram mi प्रा jai KE HC Jaz mit kt te k(22-21) (62-2) 1 1. I me kl m2 のTW ka By using Newton second dew: . mat K(x2-x) + c C2-x) = F F 6 märt klx 9 + cm x ) - 4x = 0 For steady State and transient respons The evention of motion can be written in matrix. my X t-c c il m2 ac -C -K. K X Ok tak X2 O 1 1 1 好
We hat the external force assume be harmonic int E jo z ;-ja), 2 } Fj(t): Fire Steady state solution zj(t) = xjent is The matrix equations can be written asin علم i cutk. - w²m, -6- •K icwtk اا-الان-رلیا۔ 7x? [X₂] {F. m SE [zliw = F ) Son X = 2liw) X = 20 - wmasu (w.m-iwc-K) (-we mziwek)-lick)
(261)] 1 Some scwork GEK) (owme jouw-1)- wine sew.de. Kth-licst) Liujr) -Wm-sewake x [2liol ² S., Xg.Ciw) - Cwm-cup K-PDF-O Lwin, -sce-k) ( wmz - scw-K-K) - lige X, Ciw)(-icon. k)F to (- (wym, - scwrk) (- w, my sw - K-14) lig- jut As we have at xje" Sog XICO, X, ul wt tout X1 Xze
ut X(t) = tumit scwrk-x+ F {{wymy-sw) (-wme-scayak-ke) -liqH JU Licusok E - wm - ScW-K) (wine sc w _K_K) - (icutk} for natural frequencies & mode shapes. By putting impedance matric to zen 2 ۔ نمایا۔ * ما۔ - icutk icwtk. wme-icw_k-ke. (-win-icw_k) (-w²m-icw-K-K4) - Cicutk) zo 2 ta wimmet w miict kwam, + km, w twinzica - c/w 't Klug my tuikt.com tkwini 3 Kw tX + kkt:-x-2xfiew tit mim.zmat (mi t melict' + (K[mstime) + Kem) w? twik+c+ KK, co
By assing values mi lokg: m2: 2 kg ke 590m. K: 2 N/m . / 0. F(t) = IN . 20w" tot gow? tot loco 20w" How? tloco 2 Win -8011808-41201170) 1920 40: 2 Wiak - 0.129,-3.8708 ۔ So, the First mode shape is given by X X رہا۔ (1) by it -0.6189 3-204 11.36
By putting the values in the eyustin. tt) X : -0.8189 X1 : - X = -5 TO) X 0.4401 11.36 Seand node 5 5693.71 0.0008 78 (2) 0.0065 3695 5693.77 Yes, They are indirectly connected with each other Sog ney. Decoupled. Because each of the system will depend upon other syskm. So, they interlinked thing of are
The pictures below are my answer. I want you to
correct my answer.
1X1 mi m = m = Assumed parameter values kg - sprung mass kg - unsprung mass k= N/m k = N/m N/m F(t) = N F(t) CE m2 x:(t) find the following a. The differential equations of motion. b. The transient and steady state responses. c. The natural frequencies and mode shapes d. Check if the system can be decoupled or not only check!). Write the differential equations of motion, the transient and steady state responses, the natural frequencies, and the mode shapes (from part " 42, 46, 4c" above) by substitute with the actual values of the parameters K1, K2, CI, MI, M2, etc. and reasonable values for FO and c.
Car suspension Model F Free body diagram mi प्रा jai KE HC Jaz mit kt te k(22-21) (62-2) 1 1. I me kl m2 のTW ka By using Newton second dew: . mat K(x2-x) + c C2-x) = F F 6 märt klx 9 + cm x ) - 4x = 0 For steady State and transient respons The evention of motion can be written in matrix. my X t-c c il m2 ac -C -K. K X Ok tak X2 O 1 1 1 好
We hat the external force assume be harmonic int E jo z ;-ja), 2 } Fj(t): Fire Steady state solution zj(t) = xjent is The matrix equations can be written asin علم i cutk. - w²m, -6- •K icwtk اا-الان-رلیا۔ 7x? [X₂] {F. m SE [zliw = F ) Son X = 2liw) X = 20 - wmasu (w.m-iwc-K) (-we mziwek)-lick)
(261)] 1 Some scwork GEK) (owme jouw-1)- wine sew.de. Kth-licst) Liujr) -Wm-sewake x [2liol ² S., Xg.Ciw) - Cwm-cup K-PDF-O Lwin, -sce-k) ( wmz - scw-K-K) - lige X, Ciw)(-icon. k)F to (- (wym, - scwrk) (- w, my sw - K-14) lig- jut As we have at xje" Sog XICO, X, ul wt tout X1 Xze
ut X(t) = tumit scwrk-x+ F {{wymy-sw) (-wme-scayak-ke) -liqH JU Licusok E - wm - ScW-K) (wine sc w _K_K) - (icutk} for natural frequencies & mode shapes. By putting impedance matric to zen 2 ۔ نمایا۔ * ما۔ - icutk icwtk. wme-icw_k-ke. (-win-icw_k) (-w²m-icw-K-K4) - Cicutk) zo 2 ta wimmet w miict kwam, + km, w twinzica - c/w 't Klug my tuikt.com tkwini 3 Kw tX + kkt:-x-2xfiew tit mim.zmat (mi t melict' + (K[mstime) + Kem) w? twik+c+ KK, co
By assing values mi lokg: m2: 2 kg ke 590m. K: 2 N/m . / 0. F(t) = IN . 20w" tot gow? tot loco 20w" How? tloco 2 Win -8011808-41201170) 1920 40: 2 Wiak - 0.129,-3.8708 ۔ So, the First mode shape is given by X X رہا۔ (1) by it -0.6189 3-204 11.36
By putting the values in the eyustin. tt) X : -0.8189 X1 : - X = -5 TO) X 0.4401 11.36 Seand node 5 5693.71 0.0008 78 (2) 0.0065 3695 5693.77 Yes, They are indirectly connected with each other Sog ney. Decoupled. Because each of the system will depend upon other syskm. So, they interlinked thing of are