Answer Happy

Time left 1:03:56 A projectile is fired vertically upwards at 78.48 m/s from the top of a cliff which is 200 m above ground. A second projectile is dropped downwards from the same height 6 s later. Analyze the motion of both projectile and then calculate: • The maximum height above the ground reached by the first projectile: m, • The maximum distance covered by the second projectile: т • The time taken by the first projectile to reach a point 150 m above the ground. S, • The magnitude of the speed of the first projectile after 9 seconds its launch: m/s, The heights of respective projectiles 9 s after the launch of the first projectile: . m above ground Projectile 1: and • Projectile 2: m above ground and . The difference in heights: m. Projectile 1 will take s from the initial instant of launch before hitting ground,