Mounting the circuit in Figure 1 in Tinkercad, the OPAMP output should model the following equation Y = 4X – 2 (Adder -
Posted: Fri May 20, 2022 11:44 pm
Mounting the circuit in Figure 1 in Tinkercad, the OPAMP output
should model the following equation Y = 4X – 2 (Adder -
Subtractor). Criteria for Design: V1= is the voltage of the RL
charge. V2 = is variable. Polarization of the Operational Amplifier
V+ = +15 V and V- = -15V. V3, R3, R4, R5, RL at the discretion of
the designer. R1, R2, RF1, RF2, RX (if necessary), all these
resistors are at the discretion of the designer, looking for the
values that meet the expected output from the equation given. The
entire circuit operates with direct current (DC Voltage). For the
output of the OPAMP they will have a margin of error between + –
0.8. Example: Y = 4X – 2, if X = 2 then Y = 6. Vout = 4V2 – 2, if
V2 = 2 then Vout = 6V. However, the result can be between 6.8 and
5.2.
You must fill in the following table of results, for the
different values of V2:
AM- W RX RF1 A- A A- R3 R5 R1 V3 R4 AW RL AW Op-Amp + A V2 R2 RF2
should model the following equation Y = 4X – 2 (Adder -
Subtractor). Criteria for Design: V1= is the voltage of the RL
charge. V2 = is variable. Polarization of the Operational Amplifier
V+ = +15 V and V- = -15V. V3, R3, R4, R5, RL at the discretion of
the designer. R1, R2, RF1, RF2, RX (if necessary), all these
resistors are at the discretion of the designer, looking for the
values that meet the expected output from the equation given. The
entire circuit operates with direct current (DC Voltage). For the
output of the OPAMP they will have a margin of error between + –
0.8. Example: Y = 4X – 2, if X = 2 then Y = 6. Vout = 4V2 – 2, if
V2 = 2 then Vout = 6V. However, the result can be between 6.8 and
5.2.
You must fill in the following table of results, for the
different values of V2:
AM- W RX RF1 A- A A- R3 R5 R1 V3 R4 AW RL AW Op-Amp + A V2 R2 RF2