Page 1 of 1
7. Given a QPSK signal Vopsk (t) = 2b.(t)sin(21 x 105 t) + 2be(t)cos(210 x 105t) where b.(t), b (t) take a va of -1 or 1
Posted: Fri May 20, 2022 10:56 pm
by answerhappygod
- 7 Given A Qpsk Signal Vopsk T 2b T Sin 21 X 105 T 2be T Cos 210 X 105t Where B T B T Take A Va Of 1 Or 1 1 (19.67 KiB) Viewed 23 times
7. Given a QPSK signal Vopsk (t) = 2b.(t)sin(21 x 105 t) + 2be(t)cos(210 x 105t) where b.(t), b (t) take a va of -1 or 1 every 6 seconds. For VQpsk (t), determine (1) (5%) signal power Ps; (2) (5%) symbol period T, and bit period To: (3) (5%) nominal bandwidth BQPK: (4) (5%) energy per symbol E, and energy per bit Ebi (5) (5%) minimum distance between symbols dopsk