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7. Given a QPSK signal vqpsk (t) = 2b.(t)sin(210 x 105t) + 2b.(t)cos(20 x 105) where b.(t), be(t) take a value of-1 or 1
Posted: Fri May 20, 2022 10:28 pm
by answerhappygod
- 7 Given A Qpsk Signal Vqpsk T 2b T Sin 210 X 105t 2b T Cos 20 X 105 Where B T Be T Take A Value Of 1 Or 1 1 (18.77 KiB) Viewed 9 times
7. Given a QPSK signal vqpsk (t) = 2b.(t)sin(210 x 105t) + 2b.(t)cos(20 x 105) where b.(t), be(t) take a value of-1 or 1 every 6 seconds. For Vopsk), determine (1) (5%) signal power Psi (2) (5%) symbol period T, and bit period To: (3) (5%) nominal bandwidth BQPk; (4) (5%) energy per symbol Es and energy per bit Ep; (5) (5%) minimum distance between symbols dos