Answer Happy

Assignment 10 Problem (Modules 11 & 12 - 50 pts.) A) Given For a feedback control system with an open-loop process and negative feedback described R(S) E(S) Gc(s) C(s) Gp(s) H(s) The process Gp(s), and a feedback sensor H(s) = 1 are given. A cascade compensator Gc(s) to be developed according to certain requirements assigned to different design groups, described in the table below. The use of MATLAB is required for all the plots. The solving procedure and evaluation points are given next. Each design team has an specific model of the plant and requirements, located on next page. B) Determine Activities Points Gained Step # 1 Proportional Gain Performance Test 06.0 pts Step #2 Design for Open-Loop Phase Conditions Step #3 Design for Open-Loop Magnitude Conditions 06.0 pts Step #4 Open-Loop Phase & Magnitude Specifications Achievement 15.0 pts Step #5 Frequency Response Auxiliary Information 06.0 pts Step #6 Control System Diagram with PID Control 04.0 pts Step #7 Conclusions 05.0 pts Step #8 Problem Solution Process & References 02.0 pts TOTAL 50.0 pts 06.0 pts
Design Teams Requirements Design Requirements Process Model Teams/Student ID Gp(s) T1 WN ess Gp(s) 5(0.45 + 1) 12 rls 0.6 0% (ramp) 006214 121282 076748 T2 Gp(s) 9.rs 0.6 (0.25s + 1) 130304 119405 102521 0% (ramp) T3 Gp(s)* 5 (0.45+1) () = 9 rls 0.6 105424 115047 065806 0% (ramp) T4 Gp(s) 5(0.255 + 1 15 rls 0.6 0% (ramp) 114119 127016 058931 T5 Gp(s) s(0.45 + 1) 15 rls 0.6 113416 118148 110723 0% (ramp) TS Gps) = 5(0.265+1 ) 6 rls 0.6 0% (ramp) 086341 096039 113238 T7 Gp(s) 5(0.45 + 1) = 1 6 rls 0.6 0% (ramp) 115005 111609 114727