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dy dy + dx2 dx - бу = 5е-Зх = 5e d²y dy +2 +y= ty=be = dx2 dx

Posted: Tue Nov 23, 2021 9:05 am
by answerhappygod
 1
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dy dy + dx2 dx - бу = 5е-Зх = 5e d²y dy +2 +y= ty=be = dx2 dx