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Advocat. M Gmail YouTube Maps Translate M Activate Your UCI... uc Applicar Question 8 1 pts 2000 people in Madagascar were surveyed to determine their genotype at the hemoglobin allele (Hb); the number of individuals carrying the sickle cell allele (Hb) was determined. Use the Chi- Square test to determine if the resulting data is in Hardy-Weindberg equilibrium 1320 Hb/ Hb 600 Hb/ HB 80 Hb/Hbs The Chi-Square value is 3.29 the degrees of freedom are This means the [Select) the p-valu Select) 0.5 <p<0.7 hypothesis should NOT be rejected 0.8 <p < 0.9 ρες 0.001 0.2 <p <0.3 0.8 <p<0.7 Degrees of Freedom Probability (p-value) 0.95 0.90 0.80 0.70 0.50 0.30 0.20 0.10 0.05 0.01 0.001 1 0.004 0.02 0.06 0.15 0.46 1.07 1.64 2.71 3.84 6.64 10.83 2 0.10 0.21 0.45 0.71 1.39 2.41 3.22 4.60 5.99 9.21 13.82 3 0.35 0.58 1.01 1.42 2.37 3.66 4.64 6.25 7.82 11.34 16.27 4 0.71 1.06 1.65 2.20 3.36 4.88 5.99 7.78 9.49 13.28 18.47 « Previous
Question 8 1 pts 2000 people in Madagascar were surveyed to determine their genotype at the hemoglobin allele (Hb); the number of individuals carrying the sickle cell allele (Hb) was determined. Use the Chi- Square test to determine if the resulting data is in Hardy-Weindberg equilibrium. 1320 Hb/ Hb 600 Hb/ HB 80 Hb / Hb The Chi-Square value is 3.29 the degrees of freedom are ✓ Select] 2 the p-value is Select This means the 1 3 cted Degrees of Freedom Probability (p-value) 0.95 0.90 0.80 0.70 0.50 0.30 0.20 0.10 0.05 0.01 0.001 1 0.004 0.02 0.06 0.15 0.46 1.07 1.64 2.71 3.84 6.64 10.83 2 0.10 0.21 0.45 0.71 1.39 2.41 3.22 4.60 5.99 9.21 13.82 3 0.35 0.58 1.01 1.42 2.37 3.66 4.64 6.25 7.82 11.34 16.27 4 0.71 1.06 1.65 2.20 3.36 4.88 5.99 7.78 9.49 13.28 18.47 « Previous Next MacBook Air
SOCCCD Advocat... M Gmail YouTube Maps Translate M Activate Your UCI... UCI App Question 8 17 2000 people in Madagascar were surveyed to determine their genotype at the hemoglobin allele (Hb); the number of individuals carrying the sickle cell allele (Hb) was determined. Use the Chi- Square test to determine if the resulting data is in Hardy-Weindberg equilibrium. 1320 Hb/ Hb 600 HD/HB 80 Hb/ Hb [Select) 3289 1.28 428.75 The Chi-Square value is 3.29 the degrees of freedom are 0.889 [ Select) the p-values Select] . This means the . hypothesis should NOT be rejected Degrees of Freedom Probability (p-value) 0.95 0.90 0.80 0.70 0.50 0.30 0.20 0.10 0.05 1 0.01 0.004 0.02 0.001 0.06 0.15 0.46 1.07 1.64 2.71 2 0.10 3.84 6.64 0.21 10.83 0.45 0.71 1.39 2.41 3.22 4.60 3 0.35 5.99 0.58 9.21 13.82 1.01 1.42 2.37 3.66 4.64 4 6.25 7.82 0.71 1.06 11.34 1.65 16.27 2.20 3.36 4.88 5.99 7.78 9.49 13.28 18.47 • Previous Next >