Question 1 Which is the correct equation for Keq for the following reaction: X so3?( *(aq) + SO2(g) + H20 (1) AH = :-97.
Posted: Wed May 18, 2022 1:14 pm
- Question 1 Which Is The Correct Equation For Keq For The Following Reaction X So3 Aq So2 G H20 1 Ah 97 1 (244.42 KiB) Viewed 52 times
Question 2 For the following reaction, which best describes the value of the equilibrium constant Keq: X NH4+ (aq) + NO2 (aq) N2(g) + 2H2O(1) AH = +122.4 kJ/mol Selected Answer: Keq will be equal to 1 Answers: Keq will be less than 1 Keq will be equal to 1 Keq will be greater than 1 This reaction will not have an equilibrium constant
Question 3 Given the following equation: NH4+ (aq) + NO2 (aq) N2(g) + 2H20 (1) ΔΗ = -122.4 kJ/mol How would adding H20 effect the equilibrium? Selected Answer: It would cause the equilibrium to shift to the right, favoring the products or the forward reaction. Answers: It would cause the equilibrium to shift to the right, favoring the products or the forward reaction. It would cause the equilibrium to shift to the left, favoring the reactants or the reverse reaction. It would not cause any change to the equilibrium.
Question 4 Given the following equation: x 2H+ (aq) + CO32- (aq) H20 (1) + CO2 (g) AH = -134.5 kJ/mol = How would adding sodium chloride effect the equilibrium? Selected Answer: It would cause the equilibrium to shift left, favoring the reactants or the reverse reaction. Answers: It would cause the equilibrium to shift right, favoring the products or the forward reaction. It would cause the equilibrium to shift left, favoring the reactants or the reverse reaction. It would not cause any change to the equilibrium.
Question 5 Given the following equation: OH (aq) + NH4+ (aq) + 2H20 (1) + NH3(g) + AH = -89.4 kJ/mol How would decreasing the pressure effect the equilibrium? Selected Answer: It would not effect the equilibrium. Answers: It would cause the equilibrium to shift to the right, favoring the products or the forward reaction. It would cause the equilibrium to shift to the left, favoring the reactants or the reverse reaction. It would not effect the equilibrium.