Can someone help me find standard deviation for MgO unknown?
Posted: Wed May 18, 2022 11:13 am
Can someone help me find standard deviation for MgO unknown?
3 MgO unknown Trial 1 7.9 mL Trial 2 15.6 mL Trial 3 23.1 mL Final buret reading (mL) Initial buret reading (mL) Volume of EDTA used 0 mL 7.9 mL 15.6 mL 7.9 mL 7.7 mL 7.5 mL Calculate the percentage of MgO in the sample 0.01749 X 0.0079 = 0.00012817 Moles of EDTA and MgO used 0.00012817 x 40.3040= 0.00556884 g Mgo Weight of sample: 0.25 g MgO / 5 = 0.05 Percentage of MgO in the sample: 0.00556884/0.05 x 100=11.13 Actual percentage of Mgo in the sample='12.3% Percent error ((11.13- 12.3) 12.3) 100=8.13% | Standard deviation
3 MgO unknown Trial 1 7.9 mL Trial 2 15.6 mL Trial 3 23.1 mL Final buret reading (mL) Initial buret reading (mL) Volume of EDTA used 0 mL 7.9 mL 15.6 mL 7.9 mL 7.7 mL 7.5 mL Calculate the percentage of MgO in the sample 0.01749 X 0.0079 = 0.00012817 Moles of EDTA and MgO used 0.00012817 x 40.3040= 0.00556884 g Mgo Weight of sample: 0.25 g MgO / 5 = 0.05 Percentage of MgO in the sample: 0.00556884/0.05 x 100=11.13 Actual percentage of Mgo in the sample='12.3% Percent error ((11.13- 12.3) 12.3) 100=8.13% | Standard deviation
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3 MgO unknown Trial 1 7.9 mL Trial 2 15.6 mL Trial 3 23.1 mL Final buret reading (mL) Initial buret reading (mL) Volume of EDTA used 0 mL 7.9 mL 15.6 mL 7.9 mL 7.7 mL 7.5 mL Calculate the percentage of MgO in the sample 0.01749 X 0.0079 = 0.00012817 Moles of EDTA and MgO used 0.00012817 x 40.3040= 0.00556884 g Mgo Weight of sample: 0.25 g MgO / 5 = 0.05 Percentage of MgO in the sample: 0.00556884/0.05 x 100=11.13 Actual percentage of Mgo in the sample='12.3% Percent error ((11.13- 12.3) 12.3) 100=8.13% | Standard deviation