OHM 1046 Significance of the magnitude of K Remember that the general expression for Kis given by the K for K= [Products
Posted: Wed May 18, 2022 10:23 am
up u til what does it mean when the value of K=1 please
OHM 1046 Significance of the magnitude of K Remember that the general expression for Kis given by the K for K= [Products] [Reactants) Predict whether products or reactants will dominate at equilibrium What predominates at equilibriuni Products or Reactants? Equations and K values CHI(g) HO(g) → CO(g) + 3H (9) K = 7.7 x 104 at 298K Na (g) + O. (g) → 2NO (9) Ke=4.10 x 101 at 298K No (9) + 3H2(g) → 2NH, (a) Kc = 3.7 x 104 at 25.0°C NO(g) + 2NO, (g) Ke = 5.90 x 10' at 298K FB in the following: If the value of K is large (K> 10"). the concentration of concentration of If the value of Kis small (K <10), thus concentration of concentration of What does it mean when the value of K =12 K vs. K The expression of K equilibrium could be stated in terms of molarity, K., or pressure, K derived from partial pressure of gases in atmospheres [C] [D Kc = and KP (P) & (PD) [4] (PA) & (PB) To interchange from one to the other we can use the following expression based on the idea gas law equation, PV = nRT. Kp = K (RT) where R=0.0821 Latr/mol.K T = Temperature in K An= moles of gaseous products - moles of gaseous reactants 21
OHM 1046 Significance of the magnitude of K Remember that the general expression for Kis given by the K for K= [Products] [Reactants) Predict whether products or reactants will dominate at equilibrium What predominates at equilibriuni Products or Reactants? Equations and K values CHI(g) HO(g) → CO(g) + 3H (9) K = 7.7 x 104 at 298K Na (g) + O. (g) → 2NO (9) Ke=4.10 x 101 at 298K No (9) + 3H2(g) → 2NH, (a) Kc = 3.7 x 104 at 25.0°C NO(g) + 2NO, (g) Ke = 5.90 x 10' at 298K FB in the following: If the value of K is large (K> 10"). the concentration of concentration of If the value of Kis small (K <10), thus concentration of concentration of What does it mean when the value of K =12 K vs. K The expression of K equilibrium could be stated in terms of molarity, K., or pressure, K derived from partial pressure of gases in atmospheres [C] [D Kc = and KP (P) & (PD) [4] (PA) & (PB) To interchange from one to the other we can use the following expression based on the idea gas law equation, PV = nRT. Kp = K (RT) where R=0.0821 Latr/mol.K T = Temperature in K An= moles of gaseous products - moles of gaseous reactants 21