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Figure8.1 Preparationoft-ButylChloride HO HC, CH H + H :01 CH¢+ CH;—¢ OH+ Ha CH; hydrochloric t-butanol acid (2-methyl-2

Posted: Wed May 18, 2022 10:09 am
by answerhappygod
Figure8 1 Preparationoft Butylchloride Ho Hc Ch H H 01 Ch Ch Oh Ha Ch Hydrochloric T Butanol Acid 2 Methyl 2 1
Figure8 1 Preparationoft Butylchloride Ho Hc Ch H H 01 Ch Ch Oh Ha Ch Hydrochloric T Butanol Acid 2 Methyl 2 1 (11.39 KiB) Viewed 56 times
Figure8.1 Preparationoft-ButylChloride HO HC, CH H + H :01 CH¢+ CH;—¢ OH+ Ha CH; hydrochloric t-butanol acid (2-methyl-2-propanol) CH CH cabocation la- CH t-butylchloride (2-methyl-2-chloro propane) CH- CCI
From this equation, we can say 1 mol of reactant gives 1 mol of product. Usually the amount of acid and water is taken alittle excess, so you don't need to consider them for the yield calaulation. Now you need to calculate step by step: 1. First how many grams of t-buthanol (74.12g/mol) are used to make 1 mol of t-butyl chloride n(92.57g/mol).