Answer Happy

Suggestion: Self Assessment Leaming Goal: SHM and Collision y=0 Part A (a) V21 In Drewing ), find the block m's speed v when reaching the position 11.0.213 m. Keep 3 digits after the decimal point, in meters/second x=0 x=1-4 V= m . M MIM (b) 9 AED ΑΣΦ to o ? 21 (C) at x = -0.213 m. speed of block m speed = mis Submit Request Answer In Drawing (a), a block of a mass m -0.40 kg compress a spring to r- -0.71 m and is released from rest. The spring constant is k = 800 N/m. The vertical green dashed line indicates the spring's natural length In drawing (b) the block m with the speed in part A has a head-on collision with another black M = 0.530 kg moving to the LEFT at a speed of v2i = 4.Omis. In drawing (c) after the collision, block M moves to the RIGHT at a speed of var = 3.30 m/s (c, M = s. Part B - In drawing (c) after the collision, find the VELCOITY of block m. Include a proper sign. Note: this is a colision. It's time for you to review on collisions. What physics principle to apply? . ? Keep 2 digits after the decimal point, in mis V AED ΑΣφ Drawing c), after collision velocity of block m mis Submit Request Answer Peturn to Arriamant Underlhac