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4. A 3.00 kg mass is initially at rest on a horizontal surface. After some amount of time, the has a velocity of 12.0 m/s i. The forces acting during this time are depicted below. V=0 Vf 12 m/s FApplied V F a) What was the network done on the object over this time? EW- Wrapp +Wfk = EFX (Ar) 2F-ma AKE = - + mye & mui? +3)()+ 5toto Vi=0 Vp = 12m AKE = 2/6J ? Ar AKE = EW EW-2165 b) If an applied force of 75.0 Ni was acting and the displacement over which the change in velocity took place was 4.00 m i, what was the work done by the applied force during this time? => 75N W Fopp :75 (4) - 13000 um
c) If an applied force of 75.0 Ni was acting and the displacement over which the change in velocity took place was 4.00 m i, what was the work done by the force of kinetic friction during this time? Wfhz - fk (4m) 75N 4m = 21 (4) - 1845 75- fx= 3(18) 75-3(18) = fk 2 IN - Ek V = Rmls 12²= 8 + 20 (4) 12 se 0= ? Ar 4m 8 az 18 mis d) Regarding part 'c', what must the coefficient of kinetic friction be? in- ty - mg - 3.096) – 29.4 Wee 81=Mx (29,4) 29.4 24.4 12.76-Mx 3