Determine the entropy change (J/K) when 2.8 moles of heptane are condensed at atmospheric pressure. Heptane data: 31.86
Posted: Wed May 18, 2022 8:40 am
Determine the entropy change (J/K) when 2.8 moles of heptane are condensed at atmospheric pressure. Heptane data: 31.86 kJ/mol latent heat of evaporation: standard boiling point: 98.4°C
thermodynamic relationships internal energy U = q + w enthalpy H = U + PV AH = AU + PAV gas law PV = nRT where R = 8.314 J/ mol K Hess's Law: AHR = [SAH products - [SAH) reactants = Kirchhoff's rule: (AHRST, -(AHRT, = (ACp (T2-T1) where: ACp = (Cp)(products) - E(Cp(reactants) standard molar entropy of a phase transition: AH ASE = Gibbs free energy: G = H - TS AG = AH – TAS -
thermodynamic relationships internal energy U = q + w enthalpy H = U + PV AH = AU + PAV gas law PV = nRT where R = 8.314 J/ mol K Hess's Law: AHR = [SAH products - [SAH) reactants = Kirchhoff's rule: (AHRST, -(AHRT, = (ACp (T2-T1) where: ACp = (Cp)(products) - E(Cp(reactants) standard molar entropy of a phase transition: AH ASE = Gibbs free energy: G = H - TS AG = AH – TAS -