Answer Happy

A 2.40 kg stone is sliding in the +1-direction on a horizontal, frictionless surface. It collides with a 4.00 kg stone at rest. After the collision the 2.40 kg stone is moving at 3.60 m/s at an angle of 30.0° measured from the +z-direction toward the +y-direction and the 4.00 kg stone is moving at an angle of 45.0° measured from the +x-direction toward the --y-direction. What is the y-component of momentum of the 2.40 kg stone after the collision? Express your answer with the appropriate units. ? HA Units Py2.40 kg = Value The value should be entered as a single number or in scientific notation No credit lost. Try again Submit Previous Answers Request Answer
What must be the y-component of momentum of the 4.00 kg stone after the collision? Express your answer with the appropriate units. ? НА Units Py/4.00 kg = Value Request Answer
What is the speed of the 4.00 kg stone after the collision? Express your answer with the appropriate units. CHA ? TA НА 04.00 kg Value Units
What is the x-component of the total momentum of the two stones after the collision? Express your answer with the appropriate units. HA t www ? Pz, tot = Value Units Submit Request Answer
What is the speed of the 2.40 kg stone before the collision? Express your answer with the appropriate units. Br! ? μΑ V2.40 kg = Value Units Submit Request Answer