A particle's position is given by x = 8 - 9 + 4+ (where t is in seconds and x is in meters). (a) What is its velocity at
Posted: Wed May 18, 2022 7:17 am
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A particle's position is given by x = 8 - 9 + 4+ (where t is in seconds and x is in meters). (a) What is its velocity at t = 15? (Indicate the direction with the sign of your answer.) m/s (b) Is it moving in the positive or negative direction of x just then? negative neither positive (c) What is its speed just then? m/s (d) is the speed increasing or decreasing just then? O increasing O decreasing Oneither (Try answering the next two questions without further calculation.) (e) Is there ever an instant when the velocity is zero? If so, give the time t; if not, enter NONE (1) Is there a time after t = 2.1 s when the particle is moving in the negative direction of X? If so, give the time t; if not, enter NONE.
A particle's position is given by x = 8 - 9 + 4+ (where t is in seconds and x is in meters). (a) What is its velocity at t = 15? (Indicate the direction with the sign of your answer.) m/s (b) Is it moving in the positive or negative direction of x just then? negative neither positive (c) What is its speed just then? m/s (d) is the speed increasing or decreasing just then? O increasing O decreasing Oneither (Try answering the next two questions without further calculation.) (e) Is there ever an instant when the velocity is zero? If so, give the time t; if not, enter NONE (1) Is there a time after t = 2.1 s when the particle is moving in the negative direction of X? If so, give the time t; if not, enter NONE.