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When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons isK E1 = 1.10 eV. =

Light Light 2 M Photo- electrops KE *** KE-N-W. + Photoelectric Effect Lenard found that light has to be above a certain frequency in order to observe photoelectrons 2 fo

Part A What is the maximum kinetic energy KE, of the photoelectrons when light of wavelength 320 nm falls on the same surface? Use h = 6.63x10-34 Js for Planck's constant and c = 3.00x108 m/s for the speed of light and express your answer in electron volts. 1 electron volt (eV) = 1.6 x 10-19 J. View Available Hint(s) IVO AO ? KE0 = eV Submit mv. mv2. The mass of an electron is m = 9.11x10-31 kg Part B - What is the max speed of the photoelectrons in Part A? Use the classical physics formula for KE = Use scientific notations, format 1.234-10 Ivo AD ? max speed v = m/s Submit Request Answer

Diffraction effects become significant when the width of an aperture is comparable to the wavelength of the waves being diffracted.

Part A At what speed will the de Broglie wavelength of a 68 – kg student be equal to the 0.76 – m width of a doorway? Express your answer using two significant figures. ΟΙ ΑΣΦ ? V = m/s Submit Request Answer Part B At this speed, how long will it take the student to travel a distance of 1.0 mm? (For comparison, the age of the universe is approximately 4 x 1017 s.) Express your answer using two significant figures. ΠΙ ΑΣΦ ? t = s Submit Request Answer